Grounding Conductors in Box Fill: NEC 314.16(B)(5) Explained
Understanding how to count equipment grounding conductors is one of the most misunderstood aspects of box fill calculations. NEC 314.16(B)(5) provides a special rule that can significantly affect your calculations.
The Basic Rule: All Grounds Count as One
NEC 314.16(B)(5) states that all equipment grounding conductors in a box, regardless of how many there are, count as a SINGLE conductor volume allowance based on the LARGEST equipment grounding conductor entering the box.
Key Point
Four 14 AWG ground wires = ONE × 2.00 = 2.00 cu.in. (not 8.00 cu.in.)
Why This Rule Exists
Equipment grounding conductors are typically spliced together with a single wire nut or crimp connector, taking up less space than individual terminations. The code recognizes this practical reality.
When You Have Different Ground Sizes
If your box contains equipment grounding conductors of different sizes:
- Count all grounds as ONE conductor
- Use the volume of the LARGEST ground wire
Example
A box with:
- Three 14 AWG grounds (from 15A circuits)
- One 12 AWG ground (from 20A circuit)
Calculation: 1 × 12 AWG volume = 1 × 2.25 = 2.25 cu.in.
Equipment Grounding Conductors vs. Bonding Jumpers
The 314.16(B)(5) allowance applies to:
- ✅ Equipment grounding conductors (green or bare)
- ✅ Bonding jumpers connected to the box
It does NOT apply to:
- ❌ Grounded conductors (neutral - white/gray)
- ❌ Grounding electrode conductors
Common Mistakes with Ground Wire Counting
Mistake 1: Counting Each Ground Separately
Wrong: 4 grounds × 2.00 = 8.00 cu.in.
Right: All grounds = 1 × 2.00 = 2.00 cu.in.
Mistake 2: Using Wrong Size for Mixed Grounds
Wrong: Using 14 AWG volume when 12 AWG is present
Right: Always use the LARGEST ground conductor's volume
Mistake 3: Forgetting the Pigtail
Ground pigtails that originate inside the box (from the ground splice to a device) do NOT add to the count. Only grounds entering from outside the box are counted.
Calculation Examples
Example 1: Simple Receptacle Box
| Component | Count | Volume |
|---|---|---|
| 14 AWG hot conductors | 2 | 4.00 cu.in. |
| 14 AWG neutral conductors | 2 | 4.00 cu.in. |
| 14 AWG grounds (2 wires) | 1 | 2.00 cu.in. |
| Internal clamps | 1 | 2.00 cu.in. |
| Receptacle | 2× | 4.00 cu.in. |
| Total | 16.00 cu.in. |
Example 2: Junction Box with Multiple Circuits
A box with 4 cables (8 conductors + 4 grounds) all 14 AWG:
- 8 conductors × 2.00 = 16.00 cu.in.
- 4 grounds = 1 × 2.00 = 2.00 cu.in.
- Clamps = 1 × 2.00 = 2.00 cu.in.
- Total: 20.00 cu.in.
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